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> Logic (1)> Probability> Shapes> General
> Numbers (2)> Games> Paradoxes> Riddles
> Just Math> Science> Algorithms
The annual round-table meeting pf the L&K Island's government meeting requires quorum of 5 members.
(i). Assuming that there are n members present and each one declares:
"I'm sitting between 2 Liars."
Can you estimate how many of them are Liars?

Another Liar arrives and takes a seat between 2 members and declares:
"I'm sitting between 2 Liars."
Apparently he is coherent (i.e. he lies) no matter where he placed himself.

(ii). Knowing that, would you change your answer to question (i)?

(No Solution Yet, 2 Comments) Submitted on 2017-04-24 by Ady TZIDON   
Difficulty: 2 of 5 Bonus: Changing aces (in Probability) Rating: 3.50

Four different aces are dealt, face up, one apiece, to you and three other players. They are shuffled and redealt, this time face down.

Before looking, the chance is 75% that you have an ace different from your original card.

Question 1) But what if the first player looks at his card and, without showing the card, truthfully reveals that it is not his original ace? What is the chance that you also have a different ace, given that one player's card is known to be different?

Question 2) And what if the second player also looks at his card and, without showing the card, also truthfully reveals that it is not his original ace? What is the chance that you also have a different ace, given that two players' cards are known to be different?

Question 3) Finally, what if the third player also looks at his card and, without showing the card, also truthfully reveals that it is not his original ace? What is the chance that you also have a different ace, given that all three other players' cards are known to be different?

(Solution Posted, 9 Comments) Submitted on 2005-01-31 by Steve Herman   
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