Praneeth Yalavarthi
2007-07-20 12:06:43 |
What's the next step?
Suppose you got a new idea and from that you either found a new theorem(result) or new proof to the existing theorem. What to do next? |
Brian Smith
2007-07-20 13:15:27 |
Re: What's the next step?
I suppose the next thing to do is research. Locate resources discusing the preexisting theorem and see if those resources make any statements resembling your finding. You can try looking online at MathWorld first.
If your search does not give you anything resembling your finding, then try posting at the sci.math forum on Usenet. There are several mathematicians who are willing to give feedback on sci.math to anyone with an honest question. |
Praneeth
2007-07-20 13:28:42 |
Thanx
I think its a new theorem, I searched the Mathworld, but couldn't find any related statements to it. It seems that there are many categories in it. So, where exactly can I post this? |
Brian Smith
2007-07-20 20:22:19 |
Re: What's the next step?
I usually access the sci.math forum through Google Groups. You will need to register with Google to post to the forum through them.
You could make a small post of what you found here and I would be glad to give you my opinion. |
Praneeth
2007-07-21 03:01:04 |
Here is what I think is new.
Let S(p) be {1,2,..,(p-1)} and S'(A,p) be the set of elements x from S(p) such that multiplicative order of x modulo p is A.
Sum of all the elements of the set S'(A,p) is M(A)+(1/2)*T(A)*p where
M(A): Mobius function of A and
T(A): Euler's-Totient function of A. |
Praneeth
2007-07-21 05:31:29 |
A small change
Forgot to mention that A>2 |
Praneeth
2007-07-21 05:32:45 |
So the complete statement
Let S(p) be {1,2,..,(p-1)} and S'(A,p) be the set of elements x from S(p) such that multiplicative order of x modulo p is A. Here A>2 and p is prime.
Sum of all the elements of the set S'(A,p) is M(A)+(1/2)*T(A)*p where
M(A): Mobius function of A and
T(A): Euler's-Totient function of A. |
Brian Smith
2007-07-21 12:03:27 |
Re: What's the next step?
Well, this is outside my knowledge. I would recommend trying sci.math |
