Bruce Brantley
2004-10-24 18:34:33 |
Calculus - a little help please
I’m trying to learn some calculus. The book I chose is “Barron’s College Review Series; Mathematics; Calculus”. At the end of Chapter 5, I’m supposed to find the derivative for each formula. The formula in problem 15 is:
f(s) = s^2 * (3s^2 – 6s + 9)^4
The answer in the book is:
f ’(s) = 2s * (3s^2 – 6s + 9)^3 * (15s^2 – 18s + 9)
OK, I know that 2s is the derivative of s2, but shouldn’t the derivative of
(3s^2 – 6s + 9)^4 be
4(3s^2 – 6s + 9)^3 * (6s – 6) and shouldn’t the product rule apply so that
f ’(s) = [s^2 * 4(3s^2 – 6s + 9)^3 * (6s – 6)] + [ 2s * (3s^2 – 6s + 9)^4 ]
I believe that I am wrong because glancing ahead to problem 23, which is similar, I see that I will again have the wrong answer. I’m guessing that I either started at the wrong point or I can factor out to reduce the formula to the correct answer.
A little stumped over here. Could someone provide some guidance or insight, please?
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Owl
2004-10-24 20:11:39 |
Re: Calculus - a little help please
Hi Bruce,
Try factoring as much as possible from your terms; the books answer is algebraically reduced. :-) |
Bruce Brantley
2004-10-24 20:48:45 |
Re: Calculus - a little help please
Holy Crap! Thanks Owl.
I was stuck on this problem for a several hours. I kept trying different ways of factoring, but never could find anything that would take me in the right direction.
After reading your response, I looked at it again and (3s^2 - 6s + 9)^3 jumped right out at me. I factored it out and had the answer within a minute. Funny how you get stuck some times. I got stuck on a problem in chapter 2 that had me stumped for 2 days, then "poof" it came to me. I didn't want it to take 2 days this time.
Thanks again. |
Aspiring Novice
2004-10-24 22:03:55 |
Re: Calculus - a little help please
I've been there; I feel your pain :-) |