I thought of three numbers.
Their sum is 6.
The sum of their squares is 8.
The sum of their cubes is 5.
What is the sum of their fourth powers?

I go back to my original theory....

the sum of the fourth powers (a^4 + b^4 + c^4)=64.

We could also say(a^2)^2 + (b^2)^2 + (c^2)^2, which can be written (a^2 + b^2 + c^2)^2.

We were given (a^2 + b^2 + c^2) = 8, so 8^2 = 64

Edited on July 15, 2004, 4:06 pm

Edited on July 15, 2004, 4:33 pm

Posted by Jim on 2004-07-15 15:55:57