How many ways can four points be arranged in a plane so that the six distances between pairs of points take on only two different values?
(In reply to
by )
No it isn't, Ceeane. Your rhombus is formed by equilateral
Triangles ABC and BCD, where AD is longer than AB. I have
mentioned a non-rhombus, where AD = AB = AC = BC. In my figure,
lengths BD and CD are shorter than AB.