Fill as much of a 6x6 grid with the letters A, B, C, D, E, F so no two of the same letter are in the same row, column or diagonal.
It is impossible to entirely fill the grid, but what is the largest number of letters that may be placed?
(In reply to
Possible solution. by Dej Mar)
Indeed, the last few found by the corrected program are:
4
adefcB
bAcdef
cefbad
dbaefc
eFdcba
fcbadE
4
adbfcE
bAcdef
cefbad
dbaefc
eFdcba
fceadB
4
acebfD
bfacde
cedFba
dbcAef
eafdcb
fdbeaC
4
acebfD
bfacde
cedAbf
dbcFea
eafdcb
fdbeaC
4
acebfD
bdfcae
ceAdbf
dbcfea
eFdacb
fabedC
4
acebfD
bAfcde
cedabf
dbcfea
eFadcb
fdbeaC
The corrected portions of the program involve switching rows and columns:
DECLARE SUB place (row!, col!)
CLEAR , , 9999
DIM SHARED g$(6, 6), bad(6, 6), badCt, l$, leastCt
l$ = "abcdef": leastCt = 999
FOR i = 1 TO 6
g$(i, 1) = MID$(l$, i, 1)
NEXT
place 1, 2
SUB place (row, col)
FOR i = 6 TO 1 STEP -1
lt$ = MID$(l$, i, 1)
good = 1
FOR c = 1 TO col - 1
IF g$(row, c) = lt$ THEN good = 0: EXIT FOR
NEXT
IF good THEN
FOR r = 1 TO row - 1
IF g$(r, col) = lt$ THEN good = 0: EXIT FOR
NEXT
END IF
IF good THEN
g$(row, col) = lt$
conflict = 0
FOR c = 1 TO col - 1
r = row - (col - c)
IF r > 0 THEN IF g$(r, c) = lt$ THEN conflict = 1: EXIT FOR
r = row + (col - c)
IF r < 7 THEN IF g$(r, c) = lt$ THEN conflict = 1: EXIT FOR
NEXT
bad(row, col) = conflict
IF conflict THEN badCt = badCt + 1
IF row = 6 AND col = 6 THEN
IF badCt <= leastCt THEN
leastCt = badCt
PRINT leastCt
FOR r = 1 TO 6
FOR c = 1 TO 6
IF bad(r, c) THEN
PRINT UCASE$(g$(r, c));
ELSE
PRINT g$(r, c);
END IF
NEXT
PRINT
NEXT
PRINT
END IF
ELSE
r = row + 1: c = col
IF r > 6 THEN r = 1: c = c + 1
place r, c
END IF
IF conflict THEN bad(row, col) = 0: badCt = badCt - 1
END IF
NEXT i
END SUB
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Posted by Charlie
on 2006-05-23 23:57:51 |