A  B  C  D  E  F
                  +--+--+--+--+--+--+
               1  |  |  |  |  |  |  |
                  +--+--+--+--+--+--+
               2  |  |  |  |  |  |  |
                  +--+--+--+--+--+--+
               3  |  |  |  |  |  |  |
                  +--+--+--+--+--+--+
               4  |  |  |  |  |  |  |
                  +--+--+--+--+--+--+
               5  |  |  |  |  |  |  |
                  +--+--+--+--+--+--+
               6  |  |  |  |  |  |  |
                  +--+--+--+--+--+--+
 

Each row, column and long diagonal contains two reds, two blues and two whites.

From the clues given below, can you complete the grid?

Across
1. Both the reds are somewhere to the left of both the whites.
2. Both the blues are somewhere to the right of both the reds.
3. The reds are adjacent.
4. Both the whites are to the right of the reds and blues.
5. The blues are adjacent.
6. Both the whites are somewhere to the left of both the blues.

Down
A. Both the whites are somewhere below both the blues.
B. Each red is immediately above a white.
C. There are no reds or whites in the outer cells.
D. No clue for this one.
E. The pattern (order) of colours in the upper three cells is repeated in the lower three.
F. No clue for this one.

(In reply to Solution and a Question by rs)

Hi rs,

This is the way I would do it.

On a piece of paper,I draw a large 6x6 grid.

If it says, eg "Both the reds are somewhere to the left of both the whites", I write a small B and R

 in the first two cells, and a small B and W in the last two cells.

From the across clues, my initial grid would look like this.

                    A  B  C  D  E  F
                  +--+--+--+--+--+--+
               1 |BR|BR|   |    |BW|BW|
                  +--+--+--+--+--+--+
               2 |RW|RW|  |  |BW|BW|
                  +--+--+--+--+--+--+
               3 |   |    |    |   |   |    |
                  +--+--+--+--+--+--+
               4 |RB|RB|RB|RB|W|W|
                  +--+--+--+--+--+--+
               5  |   |    |   |    |   |    |
                  +--+--+--+--+--+--+
               6 |RW|RW|  |  |RB|RB|
                  +--+--+--+--+--+--+

Then I look at the down clues.

Clue A says "Both the whites are below both the blues", So we now know that the colour in cell 2A

can only be red. There cannot be a white in 3A, because there would be only one blue above it.

Therefore the whites in column A must appear in cells 5 and 6.

If you proceed in this manner (and, importantly, don't forget the two long diagonals) the grid will

fall into place.

I do hope this helps!

If you need any more assistance, please let me know.

Josie

Ps The grid looks a bit distorted, but I hope you understand.

 

Posted by Josie Faulkner on 2006-10-31 04:04:56