(a-x) (b-x) (c-x) (d-x)........(z-x)=????
(In reply to
From (a-x) to (z-x),part 2 by Tim Axoy)
a hint for you Tim.
The answer to this equation is independant of the values chosen for the 26 variables.
To answer your question, yes the differences are being multiplied, so this is equivalent to:
(a-x)*(b-x)*(c-x)*...