If you choose three distinct integers between 1 and 63, what is more probable: that their sum will be less than 95, or greater than 95?
Mean is (1+2+3...63)/63 = 32
Thus avergae = 32*3 =96
Thus it is more probable that it is greater than 95.
|
Posted by alex
on 2007-04-11 08:20:29 |