perplexus.info :: Calculus : Maximum Value

Maximum Value (Posted on 2002-06-19)

We have :

      x^2+xy+y^2=3 and
      y^2+yz+z^2=16
      A=xy+yz+zx

Find the maximum value of A. Find x, y and z when A=max value.

(Remember the category)

See The Solution Submitted by vohonam

Rating: 3.2857 (7 votes)

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re(2): Most of a solution

| Comment 14 of 19 |

(In reply to re: Most of a solution by Cory Taylor)

Its nice to see i am not alone in tackling this problem.

With how bad the equations get, I was looking to find any solution first.
x=2/sqrt(31) y=4/sqrt(31) z=7/sqrt(31) A=8 is the only solution I have so far, but I restricted the values to positive integers to help get a handle on this thing.

Posted by Brian Smith on 2003-04-09 05:29:11

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