Given that n is a small positive integer such that:
(√3+i)
n=a, where a is a real number.
Find ⌊n-a⌋
Note: ⌊x⌋ is the floor of x, which is the greatest integer contained in x.
The complex number √3 + i has magnitude 2 and angle 30 degrees.
If n is a multiple of 6, then a will be a real number.
Let z = (√3+i)
Let n = 6
z^n = a = -2^6 = -64
n-a = 70
⌊n-a⌋ = 70
if n = 12 then a = +2^12 = 4096
n-a = ⌊n-a⌋ = -4084
If I am interpreting the problem correctly.
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Posted by Larry
on 2025-02-24 11:19:33 |