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Pandigital and Pretty Powerful V (Posted on 2023-04-20) Difficulty: 3 of 5
Determine all triplets (X, Y, Z) of base 12 positive integers such that the duodecimal representation of XY*(X+1)Z has no leading zeroes and contains each of the digits from 0 to B exactly once, with the restriction that: at least one of Y and Z is different from 1.

What is the total number of such triplets without any restriction?

  Submitted by K Sengupta    
Rating: 5.0000 (1 votes)
Solution: (Hide)
There are precisely two triplets given by:
(X,Y, Z) = (1BB, 4,1), (A084, 2,1),so that:
1BB^4 * 1BA^1 = 2740936815BA
and A084^2 * A085^1 = 70962B1345A8

For an explanation, refer to the computer program assisted solution submitted by Charlie in this location.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
re: solution, I hopeCharlie2023-04-20 22:06:24
Solutionsolution, I hopeCharlie2023-04-20 21:48:13
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