perplexus.info :: Geometry : Quadrilateral With A Difference

Quadrilateral With A Difference (Posted on 2007-11-08)

EFGH is a convex quadrilateral having diagonals EG and FH. It is known that EF = GH, while EH/FG = √3 + 1 and Angle GHE - Angle HEF = 30^o.

Determine the value of (Angle EFG - Angle FGH).

Submitted by K Sengupta

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Solution: (Hide)

Angle EFG - Angle FGH = 90^o

EXPLANATION:

Refer to the solution submitted by Bractals in this location, and by Brian Smith in this location.

Comments: ( You must be logged in to post comments.)

Subject	Author	Date
Solution	Brian Smith	2007-11-08 15:11:28
Solution	Bractals	2007-11-08 14:20:06
answer (spoiler) but no proof	Charlie	2007-11-08 12:45:05

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