perplexus.info :: Just Math : Digits 1 to B

Digits 1 to B (Posted on 2009-07-03)

An eleven digit duodecimal positive integer N is constituted by each of the nonzero digits from 1 to B exactly once, such that N satisfies all the following conditions.

The sum of the digits 1 and 2 and all the digits between them is equal to the duodecimal number 12.

The sum of the digits 2 and 3 and all the digits between them is equal to the duodecimal number 23.

The sum of the digits 3 and 4 and all the digits between them is equal to the duodecimal number 34.

The sum of the digits 4 and 5 and all the digits between them is equal to the duodecimal number 45.

The sum of the digits 5 and 6 and all the digits between them is equal to the duodecimal number 56.

If the first digit of N is more than the last digit, determine all possible value(s) that N can assume.

Note: Think of this puzzle as an extension of An ID Number Problem.

Submitted by K Sengupta

Rating: 2.0000 (1 votes)

Solution: (Hide)

67492B1A385 is the only possible value that N can assume.

For an explanation, refer to the solution submitted by ThoughtProvoker in this location.

Comments: ( You must be logged in to post comments.)

	Subject	Author	Date
	solution	ThoughtProvoker	2009-07-03 14:16:19

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