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Fathers and Sons (Posted on 2003-06-11)

Father A is twice the age of the difference in years of the ages of Father B and Son A, who is one and a half times older than Son B.

Father B is currently twice the age of Son A is going to be when Son B will be double the age he is now.

All of the ages are multiples of five.

How old is Father A?

Submitted by Lewis

Rating: 3.5000 (6 votes)

Solution: (Hide)

Son A = 15 years old.
Son B = 10 years old.
Father B = 50 years old.
Father A = 70 years old.
For an explanation, click here.

Comments: ( You must be logged in to post comments.)

Subject	Author	Date
Puzzle Solution	K Sengupta	2008-05-14 15:57:51
re(2): Most realistic solution	Dej Mar	2008-03-28 09:58:57
Answer	K Sengupta	2008-03-28 04:50:41
Solution	CharleyA.	2007-01-25 20:49:40
re: Most realistic solution	Lawrence	2003-08-24 14:29:44
Algebraic Solution	mathemagician	2003-07-05 01:34:59
No Subject	mathemagician	2003-07-05 01:13:39
one of many solutions	calla tah-n	2003-06-13 21:25:19
re:	Lewis	2003-06-12 07:44:10
No Subject	Ahmed	2003-06-12 05:04:15
re: Too easy	shaun	2003-06-12 04:13:52
Too easy	Ahmed	2003-06-12 03:58:40
re: Most realistic solution	Lewis	2003-06-11 10:33:20
Most realistic solution	Bryan	2003-06-11 08:13:52

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