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Complex Number Puzzle (
Posted on 20151108
)
Each of A, B and C is a complex number such that:
A+B+C = 2, and:
A
^{2}
+ B
^{2}
+ C
^{2}
= 3, and:
A*B*C = 4
Evaluate:
(A*B + C  1)
^{1}
+ (B*C + A  1)
^{1}
+ (C*A + B  1)
^{1}
See The Solution
Submitted by
K Sengupta
No Rating
Comments: (
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)
A more confident answer
Comment 2 of 2 
The last one was incorrect (as was my next attempt: 24/193)
New approach: try to solve for A, B, C.
I assumed A=a(cos(T)+isin(T), B=a(cos(T)isin(T)), C=c
Long story very short: the solution is 2/9
(I'll fill in the details later.)
Posted by
Jer
on 20151109 14:11:51
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