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Variety of divisors (Posted on 2015-12-03)

Find the smallest positive integer having divisors ending in 0, 1, 2, 3, ... 8, 9.

No Solution Yet Submitted by Ady TZIDON

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re: solution

| Comment 2 of 4 |

(In reply to solution by broll)

270 isn't divisible by 7 or 8.

I started with 9 and 7 since they're smaller than 19 and 17. A 5 is needed and a 4 gets us 2, 2*3=6, 2*5=10, 2*9=18. That makes 4*5*7*9=1260.

Posted by xdog on 2015-12-03 11:48:49

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