 All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars  perplexus dot info  Pair and Power Poser (Posted on 2015-11-26) Determine all possible pairs of real numbers (M,N), with M ≤ N, satisfying this system of equations:

(1+M)(1+M2)(1+M4) = 1+N7, and:
(1+N)(1+N2)(1+N4) = 1+M7

 No Solution Yet Submitted by K Sengupta No Rating Comments: ( Back to comment list | You must be logged in to post comments.) Solutions by graphing Comment 1 of 1
it isn't hard to solve the first equation for M and substitute it into the second.  Set this equal to zero.  A graph shows the solutions for (M,N) are (0,0) and (-1,-1).  But it isn't clear these are the only ones.

If you instead expand the two LHSs and do the same as before it is easy to see the resulting equation as sort of like a polynomial of degree 6 except with some terms of fractional degree between 0 and 1.  This graph shows the same two solutions and makes more clear there aren't any more.

 Posted by Jer on 2015-11-27 16:01:12 Please log in:

 Search: Search body:
Forums (0)