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N Nine Nuance (Posted on 2016-01-29) Difficulty: 3 of 5
Determine the minimum value of a positive integer N > 2 such that:
the number 199...991, containing precisely N nines, is divisible by 1991.

No Solution Yet Submitted by K Sengupta    
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re: possible solution | Comment 4 of 6 |
(In reply to possible solution by broll)

2*10^183 - 9 has a common log almost equal to the common log of 2*10^183, which is approximately 183.3...  indicating 1999...9991 has 184 digits and thus 182 9's.
  Posted by Charlie on 2016-01-29 11:11:04

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