perplexus.info :: Just Math : N Nine Nuance

N Nine Nuance (Posted on 2016-01-29)

Determine the minimum value of a positive integer N > 2 such that:
the number 199...991, containing precisely N nines, is divisible by 1991.

See The Solution Submitted by K Sengupta

Rating: 5.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)

re: possible solution

| Comment 4 of 6 |

(In reply to possible solution by broll)

2*10^183 - 9 has a common log almost equal to the common log of 2*10^183, which is approximately 183.3... indicating 1999...9991 has 184 digits and thus 182 9's.

Posted by Charlie on 2016-01-29 11:11:04

Please log in:

Login:
Password:
Remember me:

Sign up! \| Forgot password

Search:

Search body:

Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (13)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:


perplexus dot info