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N Nine Nuance (Posted on 2016-01-29) Difficulty: 3 of 5
Determine the minimum value of a positive integer N > 2 such that:
the number 199...991, containing precisely N nines, is divisible by 1991.

No Solution Yet Submitted by K Sengupta    
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re(2): possible solution | Comment 5 of 6 |
(In reply to re: possible solution by Charlie)

Well, the method's always more important than the exact result!

I was a bit fuzzy about converting n to N, but it works fine actually. If 1991 has 2 nines, then N has (180+2) = 182 nines.

Edited on January 29, 2016, 11:26 am
  Posted by broll on 2016-01-29 11:16:28

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