All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
N Nine Nuance (Posted on 2016-01-29) Difficulty: 3 of 5
Determine the minimum value of a positive integer N > 2 such that:
the number 199...991, containing precisely N nines, is divisible by 1991.

No Solution Yet Submitted by K Sengupta    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
re(2): possible solution | Comment 5 of 6 |
(In reply to re: possible solution by Charlie)

Well, the method's always more important than the exact result!

I was a bit fuzzy about converting n to N, but it works fine actually. If 1991 has 2 nines, then N has (180+2) = 182 nines.

Edited on January 29, 2016, 11:26 am
  Posted by broll on 2016-01-29 11:16:28

Please log in:
Remember me:
Sign up! | Forgot password

Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (4)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Copyright © 2002 - 2018 by Animus Pactum Consulting. All rights reserved. Privacy Information