All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Quadratic and Quintic Query (Posted on 2016-03-26) Difficulty: 3 of 5
Consider all possible positive integer solutions to the equation:
P2 + Q2 + R2 = S5

Find the minimum value of P+Q+R

No Solution Yet Submitted by K Sengupta    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
Some Thoughts A start | Comment 1 of 2
Just playing with small values of S finds:
1^2 + 11^1 + 11^2 = 3^5
5^2 + 7^2 + 13^2 = 3^5
3^2 + 3^2 + 15^2 = 3^5

The smallest value of P+Q+R is 23, from the first equality.

  Posted by Brian Smith on 2016-03-26 09:41:44
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (2)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information