Determine the total number of values of a positive integer N having at most four digits such that:
(i) The digit 1 occurs an odd number of times in N, and:
(ii) Each of the digits 2, 0 and 6 occurs an even number of times in N. (An even number includes zero), and:
(iii ) Any of the remaining six digits may or may not occur in N.
(In reply to computer solution
I think you miss something.
I don't remember my result - now away from my papers- but it was over 1000.
One of us errs, will post my solution later.