All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Odd and Even 3 (Posted on 2016-04-04) Difficulty: 3 of 5
Determine the total number of values of a positive integer N having at most four digits such that:

(i) The digit 1 occurs an odd number of times in N, and:

(ii) Each of the digits 2, 0 and 6 occurs an even number of times in N. (An even number includes zero), and:

(iii ) Any of the remaining six digits may or may not occur in N.

No Solution Yet Submitted by K Sengupta    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
re: My answers (with and without leading zeros) | Comment 4 of 6 |
(In reply to My answers (with and without leading zeros) by Ady TZIDON)

The puzzle asks that each of 2, 0, and6 occurs an even number of times.  "each"  implies individually rather than as a group.  It looks as if you consider say 62 as an even set while I consider it two odd occurrences of individual digits. 
  Posted by Charlie on 2016-04-05 13:33:52

Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (2)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information