Determine the total number of values of a positive integer N having at most four digits such that:

(i) The digit 1 occurs an odd number of times in N, and:

(ii) Each of the digits 2, 0 and 6 occurs an even number of times in N. (An even number includes zero), and:

(iii ) Any of the remaining six digits may or may not occur in N.

(In reply to

re: My answers (with and without leading zeros) by Charlie)

**Not at all .**

Read my post carefully (there was a typo I've corrected - did not affect the outcome)- and see the detailed count itemized by number of digits.

Both of us assume the same - so we must get the same answers.

Please correct me if I'M WRONG - IMHO this is not the case.

Thanks.