All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Odd and Even 3 (Posted on 2016-04-04) Difficulty: 3 of 5
Determine the total number of values of a positive integer N having at most four digits such that:

(i) The digit 1 occurs an odd number of times in N, and:

(ii) Each of the digits 2, 0 and 6 occurs an even number of times in N. (An even number includes zero), and:

(iii ) Any of the remaining six digits may or may not occur in N.

No Solution Yet Submitted by K Sengupta    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
re(3): My answers (with and without leading zeros) Comment 6 of 6 |
(In reply to re(2): My answers (with and without leading zeros) by Ady TZIDON)

You are absolutely correct  I did not initialize the counts of zeros, etc. for each new numbar and so the odd/even count was based on the total of all the numbers thus far.
  Posted by Charlie on 2016-04-05 22:28:01

Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (9)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information