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 Circle Line Length (Posted on 2016-04-07)
Each of the points P and Q lie on a circle with its center at O and having a radius of √50. Point R is inside the circle such that:
∠PQR = 90o, PQ = 6, QR = 2
Find OR

 No Solution Yet Submitted by K Sengupta No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
 Different method: Cartesian solution Comment 3 of 3 |
The circle:  x^2 + y^2 = 50
Let PQ be a horizontal line intersecting the top half of the circle.
Q is then at (3, sqrt(50-9)) = (3, sqrt(41))
P is at (-3, sqrt(41))
R is at (3, sqrt(41)-2)

distance OR is sqrt{3^2 + [sqrt(41)-2]^2}
OR = sqrt{9 + [sqrt(41)-2]^2}
OR = sqrt{9 + 41+4 -4sqrt(41)}
OR = sqrt{54 -4sqrt(41)}

OR = 5.328

 Posted by Larry on 2018-02-09 08:23:37
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