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Polynomial of degree 3n (
Posted on 20160507
)
A polynomial P(x) of degree 3n has the value 2 at x= 0, 3, 6,..., 3n, and:
the value 1 at x= 1, 4, 7, ... , 3n2, and:
the value 0 at x= 2, 5, 8, ... , 3n1.
Given that P(3n+1) = 730, find n.
No Solution Yet
Submitted by
K Sengupta
Rating:
4.0000
(2 votes)
Comments: (
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re: possible solution
 Comment 2 of 6 
(In reply to
possible solution
by Steve Herman)
P(x) = (x2)(30.5x(x1)1) , at x = 3n with n = 1,
= (3  2) (30.5 (3)(3  1)  1) = 182, not 2
Posted by
ken
on 20160508 01:02:09
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