(In reply to
Solution by Brian Smith)
'Then substitute into the first equation:
(R +/ sqrt(1003R^2))/2 + (R +/ sqrt(5763R^2))/2 = 13'
To be exact: ((5763R^2)^(1/2)R)/2+(R + (1003R^2)^(1/2))/2 =13
Then ((1003R^2)^(1/2)+(5763R^2)^(1/2))^2 = 26^2, and there is a sort of quartic, which cancels: (3009R^2)(192R^2) = 9R^4
But if so, then 576002028R^2 = 0; R^2 = 4800/169: R = 40*3^(1/2)/13, as expected.

Posted by broll
on 20160612 05:13:37 