Reciprocal Equation #2 (Posted on 2003-07-20)

	Submitted by Brian Smith
Rating: 3.4000 (5 votes)
Solution:	(Hide)
There are an infinite number of solutions. Let B=A+X. Then 1/A = 1/(A+X) + 1/C. C = 1/(1/A - 1/(A+X)) = A(A+X)/(A+X-A) = A^2/X + A. C is an integer when X is a factor of A^2. So all {A,B,C} can be expressed as {A,A+X,A^2/X + A} with A^2 mod X = 0.

	Subject	Author	Date
	Perpendicular vectors of integer length	McWorter	2005-07-19 02:00:51
	here are some...and a general	logischer Verstand	2004-05-02 22:50:50
	oops	spinoza	2003-07-23 17:05:25
	solution	spinoza	2003-07-23 17:01:56
	No Subject	Travis Taylor	2003-07-22 07:52:22
	guess	ben young	2003-07-22 05:00:14
	My first shot	Thomas	2003-07-22 04:55:39
	re: A (partial?) solution	Federico Kereki	2003-07-21 08:07:14
	A (partial?) solution	Federico Kereki	2003-07-21 07:59:33
	A (partial?) solution	Federico Kereki	2003-07-21 07:59:33
	re: Pattern (re: hmmm...)	Charlie	2003-07-20 10:47:49
	re: Pattern (re: hmmm...)	TomM	2003-07-20 07:15:11
	Pattern (re: hmmm...)	TomM	2003-07-20 06:58:49
	re: hmmm...	Charlie	2003-07-20 04:57:49
	hmmm...	Charlie	2003-07-20 04:49:28