(In reply to
Solution by Brian Smith)
I understand that the 3988gon perimeter can be calculated in this way as follows with c^2={5,8,13,20,...}
1+2+2^2, 2^2+2^2, 2^2+3^2, 2^2+4^2 etc giving the result as claimed; (1993*2+1)+((1994*1995)/2+1) = 1993003.
But other representations are possible. For example, c^2=85=2^2+9^2 but also c^2=85=6^2+7^2, with a different perimeter. 1300 has 3 different representations {2,36}{12,34}{20,30}, and so on.
Also, why does the perimeter have to be 'even', when you make a convincing case that it has to be odd?!
Edited on July 3, 2016, 6:37 am

Posted by broll
on 20160703 06:36:06 