Consider two triangles PQG and PEF, where:
E is the mid-point of PQ, and:
Points P, G and F lie on the same line, and:
QG and EF intersect at the point R
RE = 1 and, PR = PE = FG

Given that PG = x, determine PQ in terms of x.

Designing at hand, just with a pen it seems that PG=x and PQ has a quite similar lenght. 

Posted by armando on 2016-07-03 16:22:10