Consider two triangles PQG and PEF, where:
E is the mid-point of PQ, and:
Points P, G and F lie on the same line, and:
QG and EF intersect at the point R
RE = 1 and, PR = PE = FG

Given that PG = x, determine PQ in terms of x.

(In reply to Unresolved by armando)

I do think your hypothesis is correct.  Making the assumption that PG=PQ readily implies that the figure must be symmetric about line PR, with E mapping to G and Q mapping to F.

Posted by Brian Smith on 2016-07-04 12:32:51