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My four numbers (Posted on 2016-02-24) Difficulty: 3 of 5
I have in mind 4 positive numbers, which I would like you to find.

Out of the set of 6 pair-wise products of those numbers I am going to omit one.

The remaining five are: 8,10,12,24,30.

See The Solution Submitted by Ady TZIDON    
Rating: 4.3333 (3 votes)

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re(4): Solution with Analysis | Comment 10 of 12 |
(In reply to re(3): Solution with Analysis by Ady TZIDON)

All three irrational sets you listed are permutations of each other.  To see this express all the values in the form sqrt(a/b) for a,b coprime.


My original irrational set (the one Steve listed) becomes {sqrt(20/3), sqrt(48/5), sqrt(15), sqrt(60)}.  Your two additional sets are {sqrt(15), sqrt(60), sqrt(20/3), sqrt(48/5)} and {sqrt(48/5), sqrt(20/3), sqrt(60), sqrt(15)} which are just permutations.

  Posted by Brian Smith on 2016-02-25 13:57:36
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