I have in mind 4 positive numbers, which I would like you to find.
Out of the set of 6 pair-wise products of those numbers I am going to omit one.
The remaining five are: 8,10,12,24,30.
(In reply to
re(3): Solution with Analysis by Ady TZIDON)
All three irrational sets you listed are permutations of each other. To see this express all the values in the form sqrt(a/b) for a,b coprime.
My original irrational set (the one Steve listed) becomes {sqrt(20/3), sqrt(48/5), sqrt(15), sqrt(60)}. Your two additional sets are {sqrt(15), sqrt(60), sqrt(20/3), sqrt(48/5)} and {sqrt(48/5), sqrt(20/3), sqrt(60), sqrt(15)} which are just permutations.
re(4): Solution with Analysis
