Much like the third Pumpkins puzzle
six pumpkins, each having a different weight, are weighed two at a time in all 15 sets of two. This time exactly four pairs of duplicate values occurred. Those four values are 60, 100, 110, and 120 pounds.
How much did each individual pumpkin weigh?
(In reply to re: Analytical solution (Bonus puzzle question)
by Brian Smith)
Challenge accepted! I had been meaning to look for a case where the duplicates were close enough together that I could no longer start with a+d = b+c, and you presumably found one. I will try to tackle it tonight.