If
EARTH+MARS=SUNSETand
EARTHMARS=8Z0Z1 How much is Z?
Rem: analytical solution preferred.
Z = 7.
As the fivedigit EARTH plus the fourdigit MARS results in the sixdigit SUNSET... E = 9, S = 1, and U = 0.
From the rightmost digits of the subtraction: H  [1] = 1,
thus H = 2.
From the rightmost digits of the addition, [2] + [1] = T,
results in T = 3.
It then follows, [3] + R = [9], gives R = 6.
It then follows, [6] + A = (1)1, gives A = 5.
It then follows, [(1)3]  [6] = Z, results in Z = 7. At this point Z is solved; but to continue, the unused digits, 4 and 8, can be assigned. With (1+)[5] + M = N, M = 8 and N = 4.
EARTH + MARS = SUNSET
95632 + 8561 = 104193
EARTH  MARS = 8Z0Z1
95632  8561 = 87071

Posted by Dej Mar
on 20160229 08:14:00 