 All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars  perplexus dot info  Within the Galaxy (Posted on 2016-02-28) If
EARTH+MARS=SUNSET
and
EARTH-MARS=8Z0Z1

How much is Z?

Rem: analytical solution preferred.

 See The Solution Submitted by Ady TZIDON Rating: 3.0000 (1 votes) Comments: ( Back to comment list | You must be logged in to post comments.) solution Comment 2 of 2 | Z = 7.

As the five-digit EARTH plus the four-digit MARS results in the six-digit SUNSET... E = 9, S = 1, and U = 0.
From the rightmost digits of the subtraction: H -  = 1,
thus H = 2.
From the rightmost digits of the addition,  +  = T,
results in T = 3.
It then follows,  + R = , gives R = 6.
It then follows,  + A = (1)1, gives A = 5.
It then follows, [(1)3] -  = Z, results in Z = 7. At this point Z is solved; but to continue, the unused digits, 4 and 8, can be assigned. With (1+) + M = N, M = 8 and N = 4.

EARTH + MARS = SUNSET
95632 + 8561 = 104193

EARTH - MARS =  8Z0Z1
95632 - 8561 =  87071
 Posted by Dej Mar on 2016-02-29 08:14:00 Please log in:

 Search: Search body:
Forums (1)