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 Within the Galaxy (Posted on 2016-02-28)
If
EARTH+MARS=SUNSET
and
EARTH-MARS=8Z0Z1

How much is Z?

Rem: analytical solution preferred.

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 solution Comment 2 of 2 |
Z = 7.

As the five-digit EARTH plus the four-digit MARS results in the six-digit SUNSET... E = 9, S = 1, and U = 0.
From the rightmost digits of the subtraction: H - [1] = 1,
thus H = 2.
From the rightmost digits of the addition, [2] + [1] = T,
results in T = 3.
It then follows, [3] + R = [9], gives R = 6.
It then follows, [6] + A = (1)1, gives A = 5.
It then follows, [(1)3] - [6] = Z, results in Z = 7. At this point Z is solved; but to continue, the unused digits, 4 and 8, can be assigned. With (1+)[5] + M = N, M = 8 and N = 4.

EARTH + MARS = SUNSET
95632 + 8561 = 104193

EARTH - MARS =  8Z0Z1
95632 - 8561 =  87071
 Posted by Dej Mar on 2016-02-29 08:14:00

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