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Four P Pentominoes (Posted on 2016-03-04) Difficulty: 3 of 5
Four copies of the P pentomino pictured below can easily be placed in a 5x5 square without overlapping.
+--+--+--+
|  |  |  |
+--+--+--+
|  |  |
+--+--+
Prove it is impossible to put 5 copies in a 5x5 square without overlapping.

Which of the other 11 pentominoes can be included with four P pentominoes such that all five can be placed in a 5x5 square?

  Submitted by Brian Smith    
Rating: 4.0000 (1 votes)
Solution: (Hide)
The 5x5 grid below is marked with four O tiles and 21 X tiles. Any placement of a P pentomino must cover one of these four tiles. (Actually a slightly stronger statment is that any 2x2 square must cover one of these four tiles).
XXXXX
XOXOX
XXXXX
XOXOX
XXXXX
Because there are only four O tiles the maximum number of P pentominoes that can be placed is 4, meaning that it is impossible to place 5 P pentominoes in the 5x5 grid.

For any of the other pentominoes to be included with the four P pentominoes that pentomino must be placed solely on the X tiles.

The seven grids below show seven different pentominoes A-G each with four P pemtominoes P-S covering a 5x5 square.
AAAAA  BBBB   CCCC   D       EEE    FF      G
       B        C    D        E      F     GGG
                     DDD      E      FF     G

AAAAA  BBBBQ  CCCCQ  DPPPQ  PEEEQ  PFFQQ  PPPQQ
PPPQQ  BPPQQ  PPCQQ  DPPQQ  PPEQQ  PPFQQ  PPGQQ
PPQQQ  PPPQQ  PPPQQ  DDDQQ  PPEQQ  PPFFQ  RGGGQ
RRRSS  RRRSS  RRRSS  RRRSS  RRRSS  RRRSS  RRGSS
RRSSS  RRSSS  RRSSS  RRSSS  RRSSS  RRSSS  RRSSS
The three pentominoes below cannot be placed without covering an O tile, and therefore cannot cover the 5x5 square along with four P pentominoes. (Again a slightly stronger statement can be made, the skew tetromino cannot be placed without covering one of the O tiles. These three pentominoes and the P pentomino all contain the skew tetromino as a subfigure.)
 XX  XX  XXX
XX  XX  XX
 X  X
Finally, the U pentomino. Ignoring rotations and reflections there are two distinct placements for the U pentomino:
.....  UUU..
U.U..  UPU..
UUU..  PP...
.....  PP...
.....  .....
In the first figure it is impossible to place a P pentomino in the upper left. The second figure shows how one P pentomino must be placed to avoid having a gap along the left side, but there is still a gap in the bottom that cannot be filled. This shows the U pentomino cannot cover the 5x5 square along with four P pentominoes.

In summary, seven of the twelve pentominoes can be combined with 4 P pentominoes to cover a 5x5 square.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
Good workarmando2016-03-05 17:02:41
re: Sq probeSteve Herman2016-03-04 19:17:30
Sq probearmando2016-03-04 14:56:02
SolutionSolutionsJer2016-03-04 11:56:12
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