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1 to 9 concatenation (Posted on 2016-04-12) Difficulty: 3 of 5
What is the largest number n so that n, 2n, and 3n together contain every digit from 1-9 exactly once?

Analytical solution preferred.

No Solution Yet Submitted by Ady TZIDON    
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Solution Listing all n's lead to an interesting observation | Comment 4 of 7 |

I just used excel to generate a list, then stripped off the digits and looked for a sum of 45 and variance of 7.5

 n   2n  3n
192 384 576
219 438 657
273 546 819
327 654 981

What's interesting is the four solutions come as two pairs that are cycles of each other: 

192 becomes 219

384 becomes 438

576 becomes 657

The second pair cycles similarly.

(The largest n is 327)


  Posted by Jer on 2016-04-12 14:03:44
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