A and B drive from X to Y. A drives the first 40 miles, and B drives the rest of the way.
That afternoon they return by the same route, with A driving the first leg and B driving the last 50 miles.
Who drives the farthest, and by what distance?

B drives farther by 20 miles.

Let Q = the distrance between X & Y.
On the first half of the trip A drives 40 and B drives Q-40 miles.
For the second half A drives Q-50 and B drives 50.  Add the totals for A and B.
A drove 40+(Q-50)=Q-10
B drove (Q-40)+50=Q+10

The difference is 20 miles.

Posted by Kenny M on 2016-04-25 16:39:10