From the 2001 Moscow Mathematical Olympiad:
Before you are three piles of stones: one containing 51 stones, second with 49 stones, and the third 5 stones.
On each move you can either combine two piles into one or divide any pile with an even number of stones into two equal piles.
Is it possible to end up with 105 piles, each containing a single stone?
(In reply to
re: Solution by Ady TZIDON)
I was thinking the same thing. If this site ever had a major overhaul it should have the equivalent of a 'like' or 'agree' button for when someone's posted comment is as good or better than what we could give.
I came to the same conclusion with the same reasoning, so I otherwise have nothing to add.
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Posted by Jer
on 2016-05-19 07:19:50 |
re(2): Solution
