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 Colored Candy Choice (Posted on 2016-05-25)
I have 6 pieces of candy: two each of 3 different colors. They taste especially good if eaten two at a time, provided the colors are different.

These candies are in an opaque bag from which I pick two at a time. If they are different colors I eat them together (yum) but if they are the same I put them back in and draw again. I will repeat this process to eat two more.

What is the probability the last two candies will be of differing colors?

Repeat with two each of 4 colors.
Repeat with two each of 5 colors.

 No Solution Yet Submitted by Jer No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
 re(3): Second part | Comment 9 of 10 |
(In reply to re(2): Second part by armando)

I don't understand

"This is because 2d, (1d 2s) and 4s have each of them a different number of outcomes (4, 5 and 6 respectively), despite the fact that they are always four candies."

2d has only one outcome: 2s

1d 2s has two possible outcomes: 1d or 2s

4s has only one outcome: 2s

Or, if you're talking about cases of choices of the four candies, they are all 6, if you identify the candies in 2d, for example, as a1, a2, b1, b2, there are 6 combinations of these 4 taken 2 at a time.

Edited on May 26, 2016, 3:14 pm
 Posted by Charlie on 2016-05-26 15:13:50

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