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Simple number trick (Posted on 2016-06-29) Difficulty: 1 of 5
A. Have someone write down a 3 digit number.

B. You write down the same number.

C. Have them write down another 3 digit number. (Don't let them write 999.)

D. You write down the number whose digits are 9-complements to theirs. i.e. If their first digit is 7 your first digit is 2. Try not to let them notice this.

Astound them by quickly computing (A*B)+(C*D).

What's your secret?

  Submitted by Jer    
Rating: 2.5000 (2 votes)
Solution: (Hide)
There is an error in the problem. The given expression is not easy to compute in ones head. It should have been (A*C)+(B*D)

Example:
A = 379
B = 379
C = 653
D = 346

The board would look something like
379 653 379 346
To which you could add symbols to make
(379*653)+(379*346)
Which is easily computable as 378621

The trick is that since C+D=999 and A=B all you need to compute is 999*A = 1000A - A.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
SolutionAnswerMath Man2016-07-07 08:34:02
re: Likely answerJer2016-06-30 09:08:26
SolutionLikely answerSteve Herman2016-06-30 08:22:49
re: commentJer2016-06-29 10:45:33
Some ThoughtscommentCharlie2016-06-29 10:13:15
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