 All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars  perplexus dot info  Pentagonal triple triangles (Posted on 2016-07-01) Which triangular numbers are three times a pentagonal number?

Is there a geometrical interpretation to this?

 No Solution Yet Submitted by Jer No Rating Comments: ( Back to comment list | You must be logged in to post comments.) Observations on first part. | Comment 1 of 4

P(n) = (3n^2-n)/2 
T(n) = n/2(n+1)    

Say for some {T,P}, (n1)^2+(n1)=3(n2)^2-(n2).

Let (n1) = (3t-1). From :

(3t-1)^2+(3t-1) = 9t^2-3t, a promising form, since 9t^2-3t = 3(3t^2-t), three times a square, less the number squared, as in 

In general, T(3n-1) = 3P(n). It at once follows that every pentagonal number is 1/3 a triangular number.

Edited on July 1, 2016, 10:10 am
 Posted by broll on 2016-07-01 09:49:50 Please log in:
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