Home > Numbers
| Ending by 3 or 7 (Posted on 2016-08-01) |
 |
Any number ending by 3 or 7 must have at least one factor ending by 3 or 7.
Prove the above statement.
|
|
Submitted by Ady TZIDON
|
|
No Rating
|
|
|
Solution:
|
(Hide)
|
One gets a 3 s the last digit of the product from 1*3=3 or 7*9=63
7 from 1*7=7 or 3*9=27
|
Comments: (
You must be logged in to post comments.)
| |
Subject |
Author |
Date |
 | q.e.d. | Steve Herman | 2016-08-01 08:49:12 |
|
|
Please log in:
Forums (0)
Newest Problems
Random Problem
FAQ |
About This Site
Site Statistics
New Comments (19)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On
Chatterbox:
|
