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Pandigital Multiples of 99 (Posted on 2016-08-03) Difficulty: 3 of 5
How many 10 digit multiples of 99 are pandigital? Remember, no leading zeros.

No Solution Yet Submitted by Brian Smith    
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Some Thoughts re: solution 2 remarks Comment 2 of 2 |
(In reply to solution by Charlie)

Both the explanation and the result are unquestionably correct.

1. However the terms even digits and odd digits  are misleading, clearly the intention was even-positioned and odd-positioned.

2. One can get a rough order of magnitude of the result by evaluating
(10!-9!)/11 =about 296,900. The calculation is fast, but the flop side is lack of error's estimate.


  Posted by Ady TZIDON on 2016-08-03 21:12:37
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