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Right Triangle (Posted on 2003-08-05) Difficulty: 3 of 5

Given a right triangle with lengths that are reciprocals of integers, what is the smallest possible sum of these the integers?

In other words, given a right triangle with lengths 1/a, 1/b, and 1/c, where a, b, and c are all integers, what is the lowest value of a+b+c? Also, prove it.

Taken from CAML, which did not ask for a proof.

See The Solution Submitted by np_rt    
Rating: 3.4000 (5 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution One solution | Comment 2 of 12 |
Here is my solution: a = 15, b = 20, c = 12. It seems like the sum 47 would be the smallest, but I haven't found a proof yet.
  Posted by Gamer on 2003-08-05 12:47:06
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