This triplet of positive integers has this peculiarity:
A product of any its two numbers divided by the 3rd number
has 1 as a remainder.

Find it.
Show that no other exist.

(In reply to re(2): The triple without complete proof by Charlie)

if there were duplicates like a,a,b then

   two numbers divided by the 3rd number   e.g. a*b/a would never leave a remainder - you do not need computer to tell you this.

Posted by Ady TZIDON on 2016-11-01 16:16:12