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Prime candidates (Posted on 2016-12-20)

For what values of integer n are n^n + 1 and (2n)^(2n) + 1 both prime numbers?

See The Solution Submitted by Ady TZIDON

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re: solution -@ Paul

| Comment 4 of 5 |

(In reply to solution by Paul)

Excellent expose, Paul.

I would like to post it as an "official" solution, - with a small modification- after the case of n=1 the sequel will be as follows:

...Let us consider n>1.

Clearly, when n is odd - x^n + 1 is even, and therefore not prime.

Now for odd values of n etc etc

I hope to get your approval of the above clarification.

Please comment

Posted by Ady TZIDON on 2016-12-20 22:34:05

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