All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Shapes > Geometry
Hardest easy geometry problem (Posted on 2016-11-04) Difficulty: 4 of 5
Given: triangle ABC with D on AC and E on BC,
angle CAE = 10°,
angle BAE = 70°,
angle CBD = 20°, and
angle ABD = 60°.

Find angle AED using only elementary geometry (no sines, cosines , or any other trigonometry.)

No Solution Yet Submitted by Jer    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
Some Thoughts Thoughts | Comment 1 of 2

This is a fantastic problem!!!

In the following, three capital letters denote
an angle.

   I used the sine rule multiple times to derive
a formula for AED in terms of arbitrary values
for ABD, BAE, CAE, and CBD.
   It gave the correct values for AED in
Geometer's Sketchpad most of the times
(I'm still working on the other times).
   It gave AED = 20.00000 when I specified
the four values of our problem. 

   For our problem without using trig. I could
find AED = 20 (with proof) only if I could
prove the following lemma:

           The foot of the perpendicular from
        point P to side BC is the midpoint of
        line segment D'E.
           Point P is the intersection of line
        segments AE and D'E'. Points D' and E'
        are the reflections of points D and E
        about the bisector of ACB.

   I'm still trying to prove the lemma. It seems
to hold in Geometer's Sketchpad. Any hints
or help would be appreciated.

   One point I would like to make: I would not even
try this problem without  Geometer's Sketchpad.



  Posted by Bractals on 2016-11-16 15:31:08
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (8)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information