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 QUICKIE X (Posted on 2017-03-28)
Let x be a positive integer of the form 24n − 1, where n is an integer.

Prove that if a and b are positive integers such that x = ab,
then a + b is a multiple of 24.

 Submitted by Ady TZIDON No Rating Solution: (Hide) -copied Paul's perfect solution: Odd squares are all = 1 mod 8 The squares of numbers not divisible by 3 are = 1 mod 3. if ab = 24n - 1 then neither a nor b can be multiples of 2 or 3, since the RHS clearly isn't. so ab = -1 mod 24 We can safely reduce both a and b mod 24 to find a solution, and then consider: a*(24-a) = 24a - a^2 = -a^2 mod 24 but a^2 = 1 mod 8 and 1 mod 3 from the above, so a^2 = 1 mod 24 and (a, -a) is a solution mod 24. The sum of the two factors is indeed 0 mod 24. Adding multiples of 24 to either factor preserves the fact that the product = -1 mod 24, and preserves the fact that the sum = 0 mod 24. There aren't other solutions because if a*(24-a) = -1 mod 24 and a*(b) = -1 mod 24 then b = 24-a, since a has no factors in common with 24.

 Subject Author Date a bit sketchy but still a solution Paul 2017-03-29 12:23:15 re: Solution....hint/spoiler Ady TZIDON 2017-03-28 14:11:12 Solution broll 2017-03-28 12:59:57

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