All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars
 perplexus dot info

 From Tangent to Circle (Posted on 2017-01-04)
The line Ax+By=C (with C nonzero) is tangent to some circle centered at the origin.

What is the radius of that circle in terms of A, B, and C?
What is the point of tangency in terms of A, B, and C?

 No Solution Yet Submitted by Brian Smith Rating: 3.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
 solution for part 2; outline for part 1 | Comment 1 of 4
ax + by = c

by= c-ax
y= (c-ax)/b

slope = -a/b

perpendicular line through origin:

y = bx/a

which intersects original line by solving

ax + (b^2)x/a = c

(a+(b^2)/a)x = c
x = c/(a+(b^2)/a) = ca / (a^2+b^2)
y = bca / (a*(a^2+b^2))

Point of tangency:

(ca / (a^2+b^2), bca / (a*(a^2+b^2))

The radius of the circle can be found from the pythagorean theorem applied to these x and y coordinates.

Edited on January 5, 2017, 12:09 pm
 Posted by Charlie on 2017-01-04 13:38:09

 Search: Search body:
Forums (0)